Help

[OldBloke]

Dead Men Walking homework service. How can we help? :doh:

Jewelz - a bit of advice. You got the answers you wanted but, at the very least, please make an effort to understand the solution. If you can't see how the answer was derived then speak to your teacher and explain that you are struggling and need help. If you just hand in correct answers then your teacher will think (wrongly) that you are up to speed. Don't cheat yourself or the teacher.

[T-Bag]

Tips to solving Algebra if you ever need to use it and your internet is unavailable (ie for an exam).

Simplify as much as possible:
2x+ 3 -x +2 = 5
is just the same as saying
x =0
add everything with the same power together. x^2s xs and numbers can be grouped together.

Remember you can always change both sides in the same way without breaking the equation. Add 2 to each side, multiply by 8 etc. This is most useful when you "Move something" from one side to the other.

eg:

x + 3 = 0
You add -3 to both side (some would call it subtracting but there's not real difference between positive and negative numbers in this case)
x + 3 - 3 = -3
Simplify
x = -3.

Next thing to remember is factorising:
2x^2 + x + 3= 0
Moving things around won't tell you much as you've got two instances of x to different powers so you can't combine them.
If you remember one formula from maths let it be this one:
x = {-b +/- SQRT[b^2 - 4ac]}/2a
a = number of x^2
b = number of x
c = number of x^0 (lone numbers)
That will give you the roots of any quadratic even if they are negative, complex, shared.

If you don't give up on maths you might get to be cool like me and study physics. :narnar:

P.S if I've made any mistakes go easy on me, it's really late.

[Aquilifer]

...
Next thing to remember is factorising:
2x^2 + x + 3= 0
Moving things around won't tell you much as you've got two instances of x to different powers so you can't combine them.
If you remember one formula from maths let it be this one:
x = {-b +/- SQRT[b^2 - 4ac]}/2a
a = number of x^2
b = number of x
c = number of x^0 (lone numbers)
That will give you the roots of any quadratic even if they are negative, complex, shared.

Yes, that is exactly the general solution to the 2nd order polynome. I didn't write that because... a) It looks like Jewelz hasn't been taught that yet (and at least here if you use some method which hasn't been taught and the result is wrong, you get 0 points) b) it looks stupid if you input a,b,c into the formula and you have c=0.

Some more general stuff:
Generally polynome of n'th order has n roots. Some of them can be imaginary or multiples though. That means you can write it (x-r1)(x-r2)*...(x-rn)=0 where the r1,...rn are the roots. This means if you know one or more roots, you could reduce it to something simpler. E.g. If you have a 3rd order polynome and you know one root is 3, then you know it is (x-3)*f2(x)=0, where the f2 is 2nd order. And 2nd order polynome can be solved always.

[Doorman]

Yes, that is exactly the general solution to the 2nd order polynome. I didn't write that because... a) It looks like Jewelz hasn't been taught that yet (and at least here if you use some method which hasn't been taught and the result is wrong, you get 0 points) b) it looks stupid if you input a,b,c into the formula and you have c=0.

Some more general stuff:
Generally polynome of n'th order has n roots. Some of them can be imaginary or multiples though. That means you can write it (x-r1)(x-r2)*...(x-rn)=0 where the r1,...rn are the roots. This means if you know one or more roots, you could reduce it to something simpler. E.g. If you have a 3rd order polynome and you know one root is 3, then you know it is (x-3)*f2(x)=0, where the f2 is 2nd order. And 2nd order polynome can be solved always.

You're strange Marcie. :blink:

[OldBloke]

I'm sure Jewelz is avidly following this and can't wait for the next installment

[Anonymous]

I'm sure Jewelz is avidly following this and can't wait for the next installment

He might even want to start more advanced maths early

[Jewelz^]

Dead Men Walking homework service. How can we help? :doh:
 
Jewelz - a bit of advice. You got the answers you wanted but, at the very least, please make an effort to understand the solution. If you can't see how the answer was derived then speak to your teacher and explain that you are struggling and need help. If you just hand in correct answers then your teacher will think (wrongly) that you are up to speed. Don't cheat yourself or the teacher.

There was 18 other questions. but on these two i just got abit confused and sometimes it can help to be taught in others ways.
I have learnt this before but cant remember how to do them
 
Edit: and i understood the answers
Edit2: Thanks for help

[Doorman]

Next, English language. :norty:

[Jewelz^]

I actually have some redrafts to do :narnar:
got to get from a D to a C on
Frankenstein
An Inspector Calls
booring :sad:

[Browne]

Next, English language. :norty:

Couldn't resist, now could you?

[Jabbs]

I love Algebra - always have done.

BB and others, please rearrange these letters into a well known word :norty:

D S A

Couldn't resist, now could you?

Ah, Doorman was being subtle there for a moment, almost restrained!  :dribble:

[Anonymous]

D S A

Ads, its an abbreviation of advertisement :lmfao: